Engineering, 21.03.2020 03:03 shayleithomas
A) A 10-mm-diameter Brinell hardness indenter produced an indentation 2.50 mm in diameter in a steel alloy when a load of 1000 kg was used. Compute the HB of this material. (b) What will be the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used
Answers: 2
, b) 
and 
are the indenter diameter and the indentation diameter, respectively.![HB = \frac{2\cdot (1000\,kgf)}{\pi\cdot (10\,mm)^{2}} \cdot \left[\frac{1}{1-\sqrt{1-\frac{(2.50\,mm)^{2}}{(10\,mm)^{2}} } } \right]](/tpl/images/0557/1393/ba320.png)
![d = (10\,mm)\cdot\sqrt{1-\left[1-\frac{2\cdot (500\,kgf)}{\pi\cdot (300)\cdot (10\,mm)^{2}} \right]^{2}}](/tpl/images/0557/1393/a9fae.png)
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