One use of PWM is to generate variable DC voltages. While the PWM signal is not DC, you should be able to see from your results in part 1 that it has a DC component that depends on the duty cycle, D. If the voltage is applied to a system that is low pass in nature, it will respond to the DC component of the signal while being largely unaffected by the other frequency components. Assume the PWM signal is applied to the low-pass system represented by the frequency response function H(j omega) = 1/j omega tau + 1, where the time constant tau. Show that the sinusoidal steady-state output y(t) can be expressed as y(t) = C_o + sigma_n=1^infinity C_n/squareroot (omega_0 n tau)^2 + 1 cos[n omega_o t + theta_n - tan^-1 (omega_0 n tau)].