A horizontal water jet at 70 °F issues from a circular orifice in a large tank. The jet strikes a vertical plate that is normal to the axis of the jet. A force of 600 lbf is needed to hold the plate in place against the action of the jet.
If the pressure in the tank is 25 psig at point A parallel to the orifice in the tank, what is the diameter of the jet just down-stream of the orifice?

The diameter of the jet just down the orifice is 0.326 ft

Explanation:

Temperature of the horizontal water = 70⁰C

Force, F = 600 lbf

Force, F =

Mass, m = , where density of water = 62.4 lbs/ft³

V = volume

F =

Area, A = V/r

...........(1)

Applying Bernoulli's equation between point A and B on the orifice

..................(2)

At point A, the initial rest position,

At the orifice,

Making the appropriate substitution, equation (2) becomes

Put the value of

600 = 4320A

A = 600/7200

A = 0.0833 ft²

Area,

answer:

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