3. Design 2nd-order Butterworth low-pass and high-pass filters for your speakers so that the crossover takes place at 4kHz and the filters are each 6dB down at the crossover. Getting the filters to cross over at 6dB down, rather than 3dB down is the major conceptual problem you have to solve in this lab.

Explain your methodology, show your computations below, and include a schematic of the compensated system Note: The Butterworth filters of the tables assume an equal source and load resistance. This is not our case, as the amplifier will have a near zero source impedance. The normalized Butterworth coefficients for a low-pass filter with zero source impedance are 2^0.5 and 2^(-.5). To get the 40dB/decade rolloff you expect from a second-order filter, start with a series, not a shunt, element in your filters.

how is this a question? in order for me to answer it i have to understand the question

explanation:

answer:

a

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)