The slender bar is moving in general plane motion with the indicated linear and angular properties. Locate the instantaneous center of zero velocity (distances x to the right of G and y above G) and determine the magnitudes of the velocities of points A and B.

instateneous center of zero velocity is 0.5m below G and velocities of A and B are 1.949m/s and 2.661m/s respectively.

Explanation:

Calculate the velocity with respect to G

(VBG)

VBG= w × BG

w= 4rad/s

BG= 0.3

VBG= 1.2m/sec

Velocity with respect to G

V AG= w × AG

V AG= 4 × 0.3

=1.2m/s

Use cosine rule to calculate absolute velocity of B

VB= √(VG) ^2+ (VBG)^2- 2(VG) (VBG) cos 110

VB= 2.661 m/s

VA= √(VG) ^2+ (V AG)^2- 2(VG) (V AG) cos 70

=1.949m/s

The point of the intersection of the perpendiculars drawn on VA, VB and VG from A, B and G respectively is instateneous centre of rotation.

GC= VG/w

Where VG is 2 m/sec and w is 4 rad/sec

GC=2/4

GC=0.5 (vertically below G)

Therefore, instateneous center of zero velocity is 0.5m below G and velocities of A and B are 1.949m/s and 2.661m/s respectively.