The 1000-lb elevator is hoisted by the pulley system and motor M. If the motor exerts a constant force of 500 lb on the cable, determine the power that must be supplied to the motor at the instant the load has been hoisted s = 15 ft starting from rest. The motor has an efficiency of e = 0.65 Determine the power that must be supplied to the motor at the instant the load has been hoisted s = 35 ft starting from rest.

In hp:

Part B:

In hp:

Explanation:

Weight of elevator=1000-lb

Force=500 lb

s=15 ft

Force on pulley=F=3*500=1500 lb

g=

According to Newton's Second law:

According to attachment:

According to third equation of motion:

Where:

Vo is initial velocity

V is final velocity

S is final distance

So is starting distance

Output power:

In hp:

Part B:

When S=35 ft

Output power:

In hp:

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

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explanation: