A traverse starts at a known point A [E(X)=4321.404, N(Y)= 6240.562] and closes on control point D [E(X)=2009.064; N(Y)= 5652.213]. The intermediate traverse points are P, Q, and R. A fixed bearing from A to point P is given as BZAP = S33o 02’W. Observations at station P (taking back sight on A) is angle to right α = 235° 12' 30"; the angle to the right at station Q (taking back sight to station P) is β=133° 23' 19"; and angle to the right at station R (taking back sight on station Q) is ɣ= 291° 16' 45". The horizontal distances measured are as follows: DAP = 451.72 ft, DPQ =515.72 ft, DQR = 9792.83 ft, and DRB =932.81 ft. Adjust the traverse and select the correct responses from the pull down menu

a. provisional x-coordinate for point Q is
b. Azimuth Q to R (AZQR) in DD. MMSS =
c. erse precision as a representative fraction (e. g., 1: )
d. raverse misclosure (dx, dy) is
e. provisional y-coordinate for point Q is

answer:

you cant but you can report the sender

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explanation:

answer:

try looking it up that is always

explanation:

yes indeed

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answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)