How much total heat energy input is needed to raise the temperature from 20°C to 100°C for 15-kg steel container filled with 17-kg liquid? [cst = 450 J/kg. Co and cli = 4100 J/kg. Co]

Total heat energy input needed is 6116kJ

Explanation:

This problem bothers heat capacity

Assuming that the steel container and the liquid have same temperatures

Given data

Initial temperature of liquid and steel container θ1=20°C

Final temperature of liquid and steel containers θ2= 100°C

Mass of container M1 =15kg

Mass of liquid M2= 17kg

Specific heat capacity of steel container cst450 J/kg.C

Specific heat capacity of

Liquid cli = 4100 J/kg.C

We know that the heat applied is given as

Q= mcΔθ

Total heat applied = Ql + Qs

Where Ql= heat applied to liquid

Qs= heat applied to steel

Substituting our given data we have

Q= 15*450(100-20)+17*4100(100-20)

Q= 6750(80)+69700(80)

Q=540000+5576000

Q= 6116000

Q= 6116kJ

answer:

a

explanation: