A small red light-emitting diode (LED) is placed 15.0 cm below the surface of the water in a bathtub. Because of total internal reflection, a circle of red light is observed at the water surface. Light inside the circle gets out into the air, but light hitting the water surface (from below) outside the circle experiences total internal reflection. Calculate the diameter of this circle. Assume that the air above the water has an index of refraction of 1.00, and that the water has an index of refraction of 1.33. diameter

34.2 Cm

Explanation:

Lets take, Snell's law

C = 48.75°

To find radius,r of the circle, we have:

r = H tanC

Where H = 15 cm

r = 15 * tan048.75°

= 17.1 cm

Diameter = 2r

= 2 * 17.1cm

= 34.2 cm

The diameter of the circle is 34.2cm

Diameter of the circle = 34.2 cm

Explanation:

The refractive index of water, i = 1.33

Critical angle, c can be calculated as:

From the diagram attached:

Radius, r = 17.1 cm

Diameter of the circle, d = 2r

d = 2 * 17.1

d = 34.2 cm

answer:

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