All of the questions in this problem are based on the circuit below. R=10Ω,L=5mH, C=500μF. The source voltage is 10cos(200t+45LaTeX: ^{^\circ}∘). Round all of your answers to two decimal places if necessary. Omit the units. What is the inductor impedance value in ohms? First, what is the REAL part.

1) The real part of the inductor impedance is 0 Ω and

2) the imaginary part of the inductor impedance 1 Ω

3) The real part of the impedance of the capacitor is 0 Ω and

4) the imaginary part of impedance of the capacitor  is -10 Ω

5) The real part of total impedance is 10Ω

6) The Imaginary part of total impedance is -9j Ω

Explanation:

Given that R=10Ω,L=5mH,C=500μF and The source voltage is 10cos(200t+45°)

The voltage in an AC circuit is given by:

Comparing with 10cos(200t+45°), we get that the angular frequency w = 200 rad/s

A complex number given by x + jy has a real part of x and an imaginary part of y

The inductor impedance (Z) is given by:

1) The real part of the inductor impedance is 0 Ω and

2) the imaginary part of the inductor impedance 1 Ω

The impedance of the capacitor is given by:

3) The real part of the impedance of the capacitor is 0 Ω and

4) the imaginary part of impedance of the capacitor  is -10 Ω

The total impedance of the circuit is the sum of the resistance, capacitive impedance and inductive impedance. It is given by:

5) The real part of total impedance is 10Ω

6) The Imaginary part of total impedance is -9j Ω

answer:

true

explanation: