Due to loading, a line segment has length 2 m with constant normal strain 0.25. What is the original length of the line segment? Due to loading, a line segment has length 2 with constant normal strain 0.25. What is the original length of the line segment? 1.60 m 1.50 m 1.75 m 2.67 m 2.50 m 2.25 m

A

Original length = 1.60 m

Explanation: given that due to loading, a line segment has length 2 with constant normal strain 0.25

Strain is the ratio of extension to original length. That is,

Strain = e/L

If a line segment has length 2, that means:

e + L = 2

e = 2 - L

And given that the strain = 0.25

Substitute all the parameters into the formula

0.25 = ( 2 - L ) / L

Cross multiply

0.25L = 2 - L

Collect the like terms

0.25L + L = 2

1.25L = 2

L = 2/ 1.25

L = 1.6 m

Therefore, original length is 1.6 metres

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

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