If the contact surface between the 20-kg block and the ground is smooth, determine the power of force F when t = 4 s. Initially, the block is at rest

The power of force F is 115.2 W

Explanation:

Use following formula

Power  = F x V

= F cos0

= (30) x 4/5

= 24N

Now Calculate V using following formula

V = + at

= 0

a = / m

a = 24N / 20 kg

a = 1.2m /

no place value in the formula of V

V = 0 + (1.2)(4)

V = 4.8 m/s

So,

Power = x V

Power = 24 x 4.8

Power = 115.2 W

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