Engineering, 13.10.2020 04:01 evansh78

The popularity of orange juice, especially as a breakfast drink, makes it an important factor in the economy of orange-growing regions. Marketed juice has either gone through a process in which it was concentrated, or it may be a not-from-concentrate juice. Frozen concentrated juice is reconstituted before consumption. Although concentrated juices are less popular in the United States than at one time, they still have a major segment of the market. The approaches to concentrating orange juice include evaporation, freeze concentration, and reverse osmosis. Here we examine the evaporation process by focusing only on two constituents in the juice: solids and water. Fresh orange juice contains approximately 10.0 wt% solids (sugar, citric acid and other indigenous ingredients) and frozen concentrate contains approximately 45.0 wt% solids. The frozen concentrate is obtained by evaporating water from the fresh juice to produce a mixture that is approximately 67.0 wt% solids. However, so that the flavor of the concentrate will closely approximate that of fresh juice, the concentrate from the evaporator is blended with fresh orange juice (and other minor additives) to produce a final concentrate that is approximately 45.0 wt% solids. Assume a basis of 100.0 kg of fresh juice fed to the process. a) What is the mass of final concentrate produced?b) What is the fraction of fresh juice that bypasses the evaporator?

Answers: 3

Show answers

Answers

Answer from: twinkie7078

A) 22.22 kg

B) 0.1364

Explanation:

When we perform a degree of freedom (DOF) analysis on the bypass subsystem, we will have 2 unknown masses which are; (m1, m2).l with degree of freedom as 1.

Secondly, when we perform a degree of freedom analysis on the overall system, we will have 2 unknown masses namely (m3, m5) with degree of freedom as 0.

Thirdly, when we perform a degree of freedom analysis on the evaporator, we will have 3 unknown masses namely (m1, m3, m4) with Degree of freedom as 1.

Lastky,when we perform a degree of freedom analysis on mixing point, we will have 3 unknown masses namely, (m2, m4, m5) with degree of freedom as 1.

We are given;

Fresh orange = 10.0 wt% solids

Frozen juice concentrate = 45.0wt% solids

Mixture produced = 67.0 wt% solids

Final concentrate = 45.0 wt% solids

Now, making use of the overall solids balance, we have;

0.1 × 100 = 0.45(m5)

m5 = (0.1 × 100)/0.45

m5 = 22.22 kg

Making use of overall mass balance, we have;

100 kg = m3 + m5

m3 = 100 - 22.22

m3 = 77.78 kg

Now, making use of the Mixing point mass balance, we have;

m4 + m2 = m5

So; m4 + m2 = 22.22 - - - (eq 1)

Also, making use of the Mixing point solids balance, we have;

0.67m4 + 0.1m2 = 0.45m5

0.67m4 + 0.1m2 = 9.999 - - - (eq 2)

Solving eq 1 and eq 2 simultaneously, we have;

m2 = 13.64 kg

m4 = 8.58 kg

Final concentrate is m5 = 22.22 kg

Now, fraction = m2/100 = 13.64/100 = 0.1364

Answer from: Quest

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.

Answer from: Quest

angvrswer:

vfg

grfhrtrhr:

jjj

yjujuju

jujuhuyhyt

bgf

bgr

gbr

bgr

gtr

bgr

gbgbbg

bgg

bbg

bfg

dcwf

fdb

ggb

rfe

gtg

gegte

gff

dfg

gfdsax

cvfbgnh

jmhngf

dsaazxscvb

nmhgb

fvdcsxaz

zxcv

bghn

Another question on Engineering

Engineering, 04.07.2019 18:10

Air is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8-cm-outer-diameter and 0.4-m-long tubes inside which the refrigerant is evaporating at -20°c. air approaches the tube bank in the normal direction at 0°c and 1 atm with a mean velocity of 4 m/s. the tubes are arranged in-line with longitudinal and transverse pitches of sl- st 1.5 cm. there are 30 rows in the flow direction with 15 tubes in each row. determine (a) the refrigeration capacity of this system and (b) pressure drop across the tube bank. evaluate the air properties at an assumed mean temperature of -5°c and 1 atm. is this a good assumption?

Answers: 1

Answer

Engineering, 04.07.2019 18:10

Water at 70°f and streams enter the mixing chamber at the same mass flow rate, determine the temperature and the quality of the exiting stream. 0 psia is heated in a chamber by mixing it with saturated water vapor at 20 psia. if both streams enters the mixing chamber at the same mass flow rate, determine the temperature and the quality of the existing system.

Answers: 2

Answer

Engineering, 04.07.2019 18:10

Machinery that is a key part of the process and without which the plant or process cannot function is classifed as: (clo4) a)-critical machinery b)-essential machinery c)-general purpose machinery d)-none of the specified options.

Answers: 1

Answer

Engineering, 04.07.2019 18:20

Find the minimum film thickness for a journal bearing with the data below. shaft diameter, d-50 mm, clearance ratio, cdratio? 0.001, shaft speed, n 2000 rpm; bearing length. i 200 mm; eccentricity ration, ? -0.55. ( note, cdratio-ca/d) the minimum film thickness is um

Answers: 2

Answer

You know the right answer?

The popularity of orange juice, especially as a breakfast drink, makes it an important factor in the...

Questions