. Using a dilution factor of 5 to account for nonuniform mixing, what ventilation rate (cubic feet per hour) will be required to keep toluol from reaching the LFL, if 3 gal. are evaporated each hour?

Vr = 2.362097 × 10⁶

Explanation:

Given that;

Dilution factor k = 5

evaporation rate E = 3 gal per hour  = 24 pints per hour

( 1 gal = 8 pints )

now let ventilation rate be Vr

Vr = (403 × Sp.Gravity × 10⁶ × E × K) / ( Mol.Weight × L)

Lets take this values

Specific gravity = 0.9

mol.Weight = 92.13

Lfl = 1.2

K = 5

E = 24

Now we substitute

Vr = (403 × 0.9 × 10⁶ × 24 × 5) / ( 92.13 × 1.2×10⁴)

Vr = 43,524,000,000 / 1,105,560

Vr = 39368.28 ft³/min  

Vr =  39368.28 × 60 ft³/hr

Vr = 2.362097 × 10⁶

answer:

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