To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105 mm^-2 . Suppose that all the dislocations in 1000 mm^3 (1 cm^3) were somehow removed and linked end to end. Required:
a. How far (in miles) would this chain extend?
b. Now suppose that the density is increased to 1010 mm^-2 by cold working. What would be the chain length of dislocations in 1000 mm^3 of material?

Explanation:

The distance of the chain would be the product of the dislocation density and the volume of the metal.

Dislocation density =

Volume of the metal =

The chain would extend

Dislocation density =

Volume of the metal =

The chain would extend

answer:

a

explanation:

answer:

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