Calculate the reflection loss that is incident normal to the surface of a triple pane window (assume n for window glass is 1.5)

the reflection loss is 4%

Explanation:

Given that;

n for window glass is 1.5

we know that

Reflection Loss rλ = (nλ - 1)² / (nλ + 1)²

the reflection of loss rλ at normal incidence between two media with different refractive indexes rλ = n'/n, the ratio indices

where n is index of refraction of air ( 1 )

and n' is the refraction of window glass ( 1.5 )

our nλ is 1.5

so we substitute into the equation

rλ =[ (1.5 - 1)² / (1.5 + 1)²] × 100

= [0.25 / 6.25] × 100

= 0.04 × 100

= 4%

Therefore the reflection loss is 4%

do you have any options?

answer:

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explanation: