Axial forces in a column due to service loads are as follows (assume the live load used in these calculationsis less than 100 psf):Dead:150 kcompressionLive:280 kcompressionRoof Live:40 kcompressionSnow:50 kcompressionWind:120 kcompression or tensionEarthquake:200 kcompression or tension1. Compute the required axial strength, TuandPu, for this column in tension and compression usingLRFD load combinations. (Neglect self-weight.)2. Describe the loading scenario that represents the worst case tension and compression loading for thecolumn (remember, wind and earthquake loading can act in either direction).

a) attached below

b) The worst case in tension is case ( 9-7 ) b which is

  = -65k

  The worst case in compression is case ( 9-5 ) a which is

 = 670 k  

Explanation:

Given data :

D = 150k , L = 280k , Lr = 40k , s = 50k , w = ± 120k

E = ± 200k

attached below is a detailed solution to the given problem ( problem 1 )

A)  attached below

b) The worst case in tension is case ( 9-7 ) b which is

  = -65k

  The worst case in compression is case ( 9-5 ) a which is

 = 670 k  

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explanation:

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