Silicon diodes are used in bridge rectifier circuit to supply a load (1002) with 24 volts DC, computerms voltage and current, the ripple factor, and the efficiency of the rectifier.

a) 26.66 volts ,  266.2 mA

b) 0.458

c) 81%

Explanation:

load ( R )  = 100 Ω

voltage source = 24 volts DC

a) Calculate the rms voltage and current

Vrms = Vp / √ 2

where : Vp = (voltage source * ) / 2 = ( 24 *

∴ Vrms = 12 / √2  = 26.66 volts

Irms = Vrms / R = 26.66 / 100 = 0.2666 = 266.6 mA

b) Calculate the Ripple factor

Ripple factor for a bridge rectifier = √( 1.1^2 - 1 ) = 0.458

c) Calculate the efficiency of the rectifier

efficiency = ( output dc power ) / Input ac power  

                = ( 24 / 100 )^2 * 100) / ( 26.66 * 0.2666 )

                = 0.0576 * 100 / 7.11  = 0.81 = 81%

answer:

true

explanation: