Engineering, 14.05.2021 03:30 mary603
We've now seen three different was to implement efficient search structures: AVL Trees, Skip Lists, and Hash Tables. All three of these data structures solve fundamentally the same problem: organizing pieces of information based on a unique key used to find it later. Sometimes, they're basically interchangeable; it doesn't always matter which choice we make. Sometimes, one or more of them should be disqualified from consideration, because it doesn't meet a requirement that's met by at least one of the others.
In each of the scenarios listed below, briefly explain whether it matters which of these three data structures we use. If so, list which ones you've disqualified from consideration and briefly explain why.
You'll be storing information about students, keyed by a student ID. The most important operations will be looking up a student based on their ID and printing a list of students sorted by their last names.
You'll be storing calendar information for one person, keyed by the date (i. e., on each date, you'll keep track of what's on their schedule). The most important operation will be finding out what's on their schedule for the next n days (i. e., today and the next n - 1 days), where n might potentially be as much as 365.
You'll be storing information about the songs in a media collection, keyed by a combination of an artist and a title, which are both strings, and the combination of which are assumed to be unique. The most important operation will be starting with a song and finding other songs that are similar-sounding.
Answers: 1
Engineering, 03.07.2019 14:10
If the thermal strain developed in polyimide film during deposition is given as 0.0044. assume room temperature is kept at 17.3 c, and thermal coefficient of expansion for the film and the substrate are 54 x 10^-6c^-1 and 3.3 x 10^-6c^-1respectively. calculate the deposition temperature.
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Engineering, 04.07.2019 18:10
Items are similar to the free issue items, but their access is limited. (clo5) a)-bin stock items free issue b)-bin stock controlled issue c)-critical or insurance spares d)-rebuildable spares e)-consumables
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Engineering, 04.07.2019 18:10
True or false (explain) (110)[111] is a slip system in bcc metals . the {111} family in fcc contains 8 planes. resolved shear stress (rss) in single crystals is just related to the applied stress. critical resolved shear stress (crss) in single crystal metals is direct proportional to the number of defects in the structure
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Engineering, 04.07.2019 18:10
What are the two (02) benefits, which may result from a successful implementation of preventive maintenance (pm) program in an organization? (clo3)a)- lean manufacturing b)-overlapping responsibilities c)-the planner is not qualified d)-accurate contractor information e)-reduction in equipment redundancies f)-accurate stores information
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We've now seen three different was to implement efficient search structures: AVL Trees, Skip Lists,...
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