A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and a 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream consists of 6% trucks, 4% buses, and 3% recreational vehicles. The driver population adjustment factor is estimated at 0.90. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume

peak-hour volume = 1890 veh/h

Explanation:

Determine the peak-hour Volume

Applying the equation below

Vp =  v / ( PHF * N * Fg * Fdp )   ( 1 )

where :

Vp = 1250

v ( peak - hour volume ) =  ?

PHF ( peak hour factor ) = 0.84

N  = 2 lanes per direction

Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1

Fdp = 0.90

Back to equation 1

v = Vp (  PHF * N * Fg * Fdp )  

  = 1250 ( 0.84 * 2 * 1 * 0.90 )

  = 1890 veh/h

answer:

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