A 2400-lb rear-wheel drive tractor carrying 900 lb of gravel starts from rest and accelerates forward at 3ft/s2. Determine the reaction at each of the two (a) rear wheels A, (b) front wheels B.

Explanation:

The missing diagram attached to the question is shown in the attached file below:

The very first thing we need to do in other to solve this question is to determine the mass of both the tractor and the mass of the gravel

For tractor, the mass is:

For gravel, the mass is:

From the diagram, let's consider the force along the horizontal components and vertical components;

So,

Consider the algebraic sum of moments in the plane of A, with counter-clockwise moments being positive.

Replacing the value of 1181.522 lb for in equation (1)

+ 1181.522 lb = 1650 lb

= (1650 - 1181.522)lb

= 468.478 lb

The net reaction on each of the rear wheels now is:)

Now, we can determine the angle at the end of the rear wheels at which the resultant reaction force is being made in line with the horizontal

Finally, the net reaction on each of the front wheels is:

1182 lb  

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