calculate the number of gram of ammonia gas (NH3) contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm

The number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.

Explanation:

Given: Volume = 3.0 L

Temperature = 305 K

Pressure = 1.50 atm

Formula used to calculate the number of moles is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

It is known that moles is the mass of substance divided by its molar mass.

Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.

Thus, we can conclude that the number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.

answer: hi

explanation: