Joe is taking the train from his hometown to Georgetown and then back to his hometown. The distance to Georgetown is 350 miles.

How much time will Joe spend traveling on the train if the train travels at an average speed of 42 mph

Joe will spend 33.33hours travelling in the train

Explanation:

We will use two equations of motion to solve this problem.

At first, we need to know the acceleration of the train. Using v(square) = u(square) + 2×a×s

Where v is the average speed of the train; 42.

u is the initial speed; which is zero since there is no speed when there is no motion.

a is the train's acceleration; we have to calculate this.

s is the distance between Joe's hometown and Georgetown; 350 miles

Making a the subject of the formula and knowing u =0, the equation reduces to

a=v(square)/2×s

Plugging the numbers

a= 42(square)/2×350

a=2.52 mph(square)

Furthermore, using another equation of motion to obtain time of travel between Joe's hometown and Georgetown

s=(u×t) + 1/2(a×t(square))

u=0 (from previous explanation) making u×t=0

s=350mph

a= 2.52mph(square)

Making t the subject of the formula

t= square root((2×s)/a)

t=square root((2×350)/2.52)

Solving the equation,

t=square root(277.778)

t=16.67 hours

Since it is a to and fro journey, we will multiply 16.67 hours by to cater for the return journey.

Total time =2×16.67

Total time= 33.33 hours

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