For some hypothetical metal the equilibrium number of vacancies at 750 degrees Celsius is 2.8x1024 m^-3. If the density and atomic weight of this metal are 5.60 g/cm3 and 65.6 g/mol, respectively, calculate the fraction of vacancies for this metal at 750 degress Celsius.

1.90× 10^4

Explanation:

The ratio of the equilibrium number of vacancies given in the problem statement (Nv= 2.3 x 10^25m^3) and the value of N is obtained using this formula N=NAp/A .

Thus;

The fraction of vacancies is equal to the Nv/Nratio.

Firstly the value of N is obtained with N=NAp/A

=( (6.022 x 10^23 atoms/mol)(5.60 g/cm3 )(10^6cm^3/m^3) )/65.6 g/mol

= 2.83 x 10^28atoms/m^3

The fraction of vacancies is Nv/Nratio:

Nv = 2.8x10^24 m^-3.

N = 2.83×10^28atoms/m^3

= 1.90× 10^4

the service industry in the united states grew in the late 1800s. what was one effect of that growth?

the number of people with jobs in factories as unskilled workers decreased.

the number of people with jobs in factories as unskilled workers increased.

the middle class grew as people took jobs as clerks, lawyers, and teachers.

the middle class shrank as people left jobs as clerks, lawyers, and teachers.

yes

explanation: