English, 11.03.2021 20:30 mackenziepaige6525

What does okonkwo consider to be the most important mark of a successful man in his village?

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Answer from: Quest

1. read the following excerpt from franklin d. roosevelt's "fireside chat 19":

on the other side of the picture, we must learn also to know that guerilla warfare against the germans in, let us say serbia or norway, us; that a successful russian offensive against the germans us; and that british successes on land or sea in any part of the world strengthen our hands.

remember always that germany and italy, regardless of any formal declaration of war, consider themselves at war with the united states at this moment just as much as they consider themselves at war with britain or russia. and germany puts all the other republics of the americas into the same category of enemies. the people of our sister republics of this hemisphere can be honored by that fact.

the true goal we seek is far above and beyond the ugly field of battle. when we resort to force, as now we must, we are determined that this force shall be directed toward ultimate good as well as against immediate evil. we americans are not destroyers — we are builders.

analyze the effectiveness of this excerpt. how does it function within the speech as a whole? how does the structure of the excerpt to convey the speech's purpose and key points? support your argument with evidence from the speech. (10 points)

Answer from: Quest

the correct answer is: [c]:

→ " leave it out. "

hope this is to you!

best wishes!

Answer from: Quest

the star of david was known as the jewish star : d

Answer from: Quest

the boy's acceleration toward the girl is 2.08 m/s^2.

explanation:

according the newton's third law, the force causing the girl accelerate towards the boy will be me with equal counter-force causing the boy to accelerate towards the girl. these forces will be of equal magnitude and allows us to determine the boy's acceleration:

$f_{boy} = f_{girl}\\f_{girl} = m_{girl}\cdot a_{girl} = 37kg\cdot 3.2 \frac{m}{s^2}=118.40n\\\implies f_{boy} = 118.40n\\a_{boy} = \frac{f_{boy}}{m_{boy}}=\frac{118.4n}{57kg}=2.08\frac{m}{s^2}$

the boy's acceleration toward the girl is 2.08 m/s^2.

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