1-SinQ = (sec Q tanQ)2
1+sinQ​

The answer is below

Explanation:

Prove that:

Trigonometric identities are equalities involving trigonometric functions for which both sides of the equality are equal and defined. Some trigonometric identities are:

sin²Ф + cos²Ф = 1;  1/cosФ = secФ; 1/sinФ = cosecФ; cosФ/sinФ = cotФ; 1 +  tan²Ф = sec²Ф

Given:

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