A steel aircraft carrier is 371 m long when moving through the icy North Atlantic at a temperature of 2.5° C. By how much does the carrier lengthen when it is traveling in the warm Mediterranean Sea at a temperature of 20° C?

The carrier lengthen by 7.79 × 10⁻² m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C

Explanation:

The initial length of steel () = 371 m

The change in length = ΔL

The change in temperature (ΔT) = 20°C - 2.5°C = 17.5°C

The coefficient of linear expansion of steel (α) = 12 × 10⁻⁶ ⁰C⁻¹

ΔL = αL₀ΔT = 371 × 17.5 ×  12 × 10⁻⁶ = 7.79 × 10⁻² m

The carrier lengthen by 7.79 × 10⁻² m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C

(4,-2)

explanation:

6x+4y=16

-6x-9y=-6

-5y=10

y=-2

x=4