The first steps in determining the perimeter of triangle ABC are shown. NO
5
A
to
1-2 31
2
|(1, 3)
AB = 3
BC = 5
1
CA = V(1+2)2+(-2-3)?
= √(3)² + (-5)²
4
5
х
5 4 3 2 -11 A 2.
-2
-3
C (1.-2)

Maybe a horizontal because its a pattern

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