The first term of an arithmetic sequence is 11. It's 32nd term is 600. Determine the sum of the first 50 terms of this sequence.

The sum of the first 50 terms is 23825

Explanation:

You posted this question in the wrong subject; This is mathematics not geography; However, the solution is as follows

Given

First Term: 11

32nd Term = 600

Required

Sum of first 50 terms

Using proper notations

First the common difference has to be calculated;

The nth term of an arithmetic sequence is as follows

Where d represents the common difference

Using the data for ; Substitute 11 for a and 32 for n

Recall that

The above expression becomes

Subtract 11 from both sides

Divide both sides by 31

At this point the sum of first 50 terms can be calculates;

Substitute a = 11; n = 50 and d = 19

Start by solving the inner brackets

Hence, the sum of the first 50 terms is 23825

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