Triangle ABC has a right angle at C. Next, side AB=7m and side CB=4m. Using inverse trigonometric functions, find the degree measures of angle B and angle A.​

A = 34.85°

B = 55.15°

Explanation:

From the diagram attached :

Using inverse trigonometry :

Angle A ;

Sin A = opposite / hypotenus

Tan A = 4 /7

Angle A = sin^-1(4 / 7)

Angle A = sin^-1(0.5714285)

A = 34.849904

A = 34.85°

Angle B;

Cos B = Adjacent / hypotenus

Cos B = 4/7

B = Cos^-1(4/7)

B = cos^-1 0.5714285

B = 55.150095

B = 55.15°

answer d to the question