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Health, 21.12.2020 21:00 SapphireWolf

Given that f:x ->kx +m and g:x -> cx+d, prove that fg=gf <=> d(k-1) =m(c-1).

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Given that f:x ->kx +m and g:x -> cx+d, prove that fg=gf <=> d(k-1) =m(c-1)....
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