During the analysis, 0.00905 mol h2o is formed. calculate the amount of h atoms in 0.00905 mol h2o.

The amount of H atoms in 0.00905 mole H₂O is 1.09×10²² atoms

Determination of the mole of H in 0.00905 mole H₂O

1 mole of H₂O = 2 moles of H

Therefore,

0.00905 mole H₂O = 0.00905 × 2

0.00905 mole H₂O = 0.0181 mole of H

How to determine the number of atoms in 0.0181 mole of H

From Avogadro's hypothesis,

1 mole of H = 6.02×10²³ atoms

Therefore,

0.0181 mole of H = 0.0181 × 6.02×10²³

0.0181 mole of H = 1.09×10²² atoms

Thus, 1.09×10²² atoms of H is present in 0.00905 mole H₂O

Learn more about Avogadro's number:

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In H2O there are two atoms of hydrogens and one atom of oxygen. To calculate the number of atoms, you need to multiply the atoms in mol unit with Avogadro number. Then the number of H atoms in 0.00905 mol H2O should be:

0.00905 mol * 2 * 6.02 * 10^23=
0.108962 * 10^23 atoms=
1.08962 * 10^22 atoms

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