The principal of a school surveyed 200 students on the time they spent on the Internet after school . The mean and the standard deviation of the sample data are 2.4 hours and 0.8 hours , respectively . What is the margin of error for 95 % confidence interval ?

11%

Explanation:

Sample size, n = 200

Mean, m = 2.4

Standard deviation, s = 0.8

Z critical at 95% = 1.96

Margin of Error = Zcritical * sqrt(s^2 / n)

Margin of Error = 1.96 * sqrt(0.0032)

Margin of Error = 1.96 * 0.0565685

Margin of Error = 0.1108743

Hence, margin of error at 95% confidence interval is (0.1108743 * 100%) = 11.08% = 11%

the catholic church withhold people's access to the bible during the middle ages.

people could go to church and listen to the teachings, but it was absolutely forbidden to own and/or read the books of both the old and new testaments. it was also prohibited to translate the books (which where originally in biblical hebrew) to any other language.

this was done so the church could remain in control of what their teachings were and to enhance their importance and power, while also being able to judge people's actions through information that was unavailable for the general public.

music

explanation: