History, 23.08.2019 20:00 StephenSudu

Another name for the counter-reformation of the 1500s was the catholic reformation. the english reformation. the german reformation. the protestant reformation.

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Answer from: frank2010

Base on the question that wants to choose among the following choices that states the other name for the counter reformation of the 1500's and I think the best answer among them, base on my own research, is the Protestant Reformation. I hope you are satisfied with my answer and feel free to ask for more

Answer from: taiyana74

The correct answer here is the first option.

The Counter-Reformation is also known as the Catholic Reformation. The Catholic Reformation occurred as a response the increasing rise of the Protestant Reformation and the creation of protestantism as many have become critical of the Catholic Church and have split from it. The Counter-Reformation began with the Council of Trent.

Answer from: Quest

the correct answers are the following

a proxy war which functioned as a training field for wwii

republican democratic goverment

national side, leaded by the fascist general franco

the spanish civil war took place between 1936 and 1939 and was fought after a military coup undertaken on the 17th july 1936 by a group of generals that had seceeded from the spanish republican army, under the leadership of general franco, and who aimed to expel the democractically-elected republican goverment from power.

this war became a proxy war in which european powers tested their military equipment. on one side, urss and mexico supported the left-wing republican spanish goverment, while nazi germany and fascist italy supported the national fascist side.

franco managed to win the war in 1939, with the significant contribution of the foreign military support, and became the dictator of spain until his death in 1975.

explanation:

mark brainliest and have a great day!

Answer from: Quest

answer

$x = \pm 2\sqrt{2} \: \: or \: \: x = \pm 1$

explanation

the given equation is

${x}^{4} - 9 {x}^{2} + 8 = 0$

we can rewrite this as:

$({x}^{2})^{2} - 9 {x}^{2} + 8 = 0$

let

$u = {x}^{2}$

then the equation becomes:

${u}^{2} - 9 {u}^{2} + 8 = 0$

the factors of 8 that sum up to -9 are {-1,-8}

we split the middle term with these factors to obtain,

${u}^{2} - u - 8u+ 8 = 0$

we factor by grouping to obtain:

$u(u - 1) - 8(u - 1) = 0$

$(u - 8)(u - 1) = 0$

apply the zero product property to get:

$u - 8 = 0 \: \: or \: \: u - 1 = 0$

$u = 8 \: or \: u = 1$

but

$u = {x}^{2}$

${x}^{2} = 8 \: or \: {x}^{2} = 1$

$x = \pm \sqrt{8} \: \: or \: \: x = \pm \: \sqrt{ 1}$

$x = \pm 2\sqrt{2} \: \: or \: \: x = \pm 1$

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