Given: abcd is a trapezoid, ac ⊥ cd ab = cd, ac=the square root of 75 , ab = 5 find: aabcd

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that  and BF= . Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  

its 4 because 2 times 2 is 4, if you double the number two you get four

omg what happend to your question? if you could edit this question i can

step-by-step explanation: