Use the spinner shown. it is equally probable that the pointer will land on any one of the six regions. if the pointer lands on a borderline, spin again. if the pointer is spun twice, find the probability that it will land on grey and then purple

Probability that it will land on grey and then purple is .

Step-by-step explanation:

Given: it is equally probable that the pointer will land on any one of the six regions. if the pointer lands on a borderline, spin again.

According to question:  if the pointer is spun twice, then we have to determine the probability that it will land on grey and the purple.

There are six regions which means there are equally probabilities for the pointer to land on grey and the purple.

Now,

If each region has a colour the probability for it to land on is:

The numerator represents the only green or purple possibilities for there is only one region with each colour.

Therefore, probability that it will land on grey and then purple is .

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step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b