Find the total area the regular pyramid. t. a. =

The answer would be   A = 54raiz (3) + 18raiz (91)
Formula:
 A = Ab + Al Where, Ab=base area A= lateral area

 The area of the base is: Ab = (3/2) * (L ^ 2) * (root (3)) Where, L= side of the hexagon. Substitute: Ab = (3/2) * (6 ^ 2) * (root (3)) Ab = (3/2) * (36) * (root (3)) Ab = 54raiz (3)

 The lateral area is: Al = (6) * (1/2) * (b) * (h) Where, b= base of the triangle h= height of the triangle Substitute: Al = (6) * (1/2) * (6) * (root ((8) ^ 2 + ((root (3) / 2) * (6)) ^ 2)) Al = 18 * (root (64 + 27)) Al = 18raiz (91)

 The total area is: A = 54raiz (3) + 18raiz (91)

The decimal expansion would be .27 repeated