Noise in a quiet room is 500 times as intense as the threshold of sound. what is the decibel measurement for the quiet room?

27 db

Step-by-step explanation:

I₀ = threshold of sound = 1 x 10⁻¹² W/m²

I = intensity of sound in the room = 500 I₀ = 500 x 1 x 10⁻¹² =  500 x 10⁻¹² W/m²

β = Sound level in decibel in the quiet room

Sound level in decibel in the quiet room is given as

β = 10 log₁₀(I/I₀)

inserting the values

β = 10 log₁₀((500 x 10⁻¹²)/(1 x 10⁻¹²))

β = 27 db

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: what do you mean