Mona is skating at a speed of 300 feet per minute. lina is 1000 feet behind her. what should be her speed if she wants to catch up with mona in 10 minutes?

If we translate the facts into location equations, xM=Mona's location, xL=Lina's location, then we get:

xM(t) = 300t
xL(t) = v*t - 1000
xM(10)=xL(10)

Where v is Lina's speed we have to find.

Plugging them all together gives:

300*10 = 10v - 1000 

Which can be solved:

3000 + 1000 = 10v
4000 = 10v
v=400

Lina should skate at 400 feet per minute!

Iagree that is the answer to the question