Im ading and subtracting rational expression. my question is 5 is the numerator 2x -1 is the denominator + 6x +7 and 1 -4x squared

It's my method of solving this type of account, i get the denominators and multiply them by the fractions, then you cut the denominators, any questions just ask, i don't think that it was clarifying:

(2x-1) . (1-4x^2) . (5/2x-1) + (2x-1) . (1-4x^2) . (6x/1-4x^2) =
-> (1-4x^2) . 5 + (2x-1) . 6x =
-> 5 - 20x^2 + 12x^2 - 6x =
-> -8x^2 - 6x + 5 = 0

Delta = (-6)^2 - 4.(-8).5
Delta = 36 + 160 = 196

x' = - (-6) + sqroot(196) / 2.(-8)
x' = 6 + 16 / -16
x' = 22/-16 (simplifying by 2) = -11/8

x'' = 6 - 16 / -16 = -10/-16 (simplifying by 2)
x'' = 5/8