Find the probability that a point chosen randomly inside the rectangle is in each given shape. round answers to the nearest hundreth. i need the percent.

9)    20.93%

10)  20%

11)   40.93%    

12)   59.07%    

We are given a rectangle of dimensions 10ft×6ft which inscribes:

Hence,

Here we have: r= 2ft.

Hence, Area of circle=(3.14)×(2)²

                                  = 12.56 square ft.

                                 =1/2×(4+2)×4

                                 = 12 square ft.

                                                = 10×6

                                                = 60 square ft.

Ques 9)

Probability that a point chosen lie on circle is:

  Area of circle/Area of rectangle

= 12.56/60

= 0.2093333

In percent it is given by: 20.93%

Ques 10)

Probability that a point chosen lie on trapezoid is:

  Area of trapezoid/Area of rectangle

= 12/60

= 0.2

In percent it is given by: 20%

Ques 11)

The circle or trapezoid is:

Probability that a point is chosen on circle+Probability that it is chosen on trapezoid.

= 40.93%

( Since,

P(A∪B)=P(A)+P(B)-P(A∩B)

and as circle and trapezoid do not have anything in common.

Hence, A∩B=∅

Hence, P(A∩B)=∅

Hence, P(A∪B)=P(A)+P(B)    )

Ques 12)

Not the circle and the trapezoid this means that the point will lie in the shaded region.

Hence, Probability is:

100%-Probability(it will lie either on circle or trapezoid)

=100%-40.93%

=59.07%

answer: i forgot

step-by-step explanation:

the answer to this question is in the pic