The amount of a sample remaining after t days is given by the equation mc001-1.jpg, where a is the initial amount of the sample and h is the half-life, in days, of the substance. a scientist has a 10-mg sample of a radioactive isotope. the isotope has a half-life of 8 days. after 16 days, how much of the radioactive isotope remains? 2.0 mg 2.5 mg 5.7 mg 7.1 mg

P(t)= A(1/2)^(t/h)

P(t)=10(1/2)^(16/8)

(1/2)^(16/8) =.25

P(t)=10(.25)

P(t)=2.5

Therefore the answer is B. 2.5mg.

b. 2.5 mg

just took the test on edge

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)