Amodel rocket is launched from the ground with an initial velocity of 120 feet per second. the height of an object h, in feet, after t seconds, with initial velocity v0 and initial height h0 is given by h(t)=−16t2+v0t+h0 . what is the approximate maximum height the rocket reaches?

The rocket will reach a maximum height of 225 feet from the ground in 3.75 seconds.      

Step-by-step explanation:

We are given the following information in the question:

Initial velocity = = 120 feet per second

Initial heigth =

h(t) is a function of t that gives height of the rocket at time t, initial velocity . intial height .

Differentiating h(t) with respect to t, we get:

Equating the first derivative to zero,

Again differentiating, h(t) with respect to t,

Hence, h(t) will have a local maxima by double derivative test.

Maximum height attained by rocket =

Hence, the rocket will reach a maximum height of 225 feet from the ground in 3.75 seconds.

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9