Natasha wants to use the fermi process to estimate the number of pennies that would fill a toy chest. as part of the process, she needs to estimate the volume of the toy chest. she figures the toy chest is about 50 in. long, 20 in. wide, and 20 in. tall. which estimate best approximates the volume of the toy chest? 2×103 in³ 2×104 in³ 2×105 in³ 2×106 in³

Dimension of toy chest

Length =50 inches

Width = 20 inches

Height = 20 inches

Volume of toy chest = Length × Breadth ×Height

                                 = 50 ×20 × 20

                                 = 1000 × 20

                                 = 20,000 inches cube.

    appears best approximation.

Option B

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube