Jimmy and rick are practicing knot-tying for their rock climbing training.  the number of knots that jimmy can complete in  x  days  is modeled by the function  f(x) = 6x  + 10,  and the number of knots rick can complete in  x  days  is modeled by the function  g(x) = 4x  + 15after x days, the function that models how many more knots jimmy can complete than rick is given by h(x)=_x

For this case we have the following functions:
 For Jimmy:
 f (x) = 6x + 10
 For Rick:
 g (x) = 4x + 15
 We subtract both functions:
 h (x) = f (x) - g (x)
 Substituting we have:
 h (x) = (6x + 10) - (4x + 15)
 h (x) = 2x - 5
 
 the function that models how many more knots Jimmy can complete than Rick is given by:
 h (x) = 2x - 5

The number of knots that Jimmy can complete in x days is modeled by the function⇒⇒⇒⇒  f(x) = 6x + 10

the number of knots Rick can complete in x days is modeled by the function ⇒⇒⇒⇒ g(x) = 4x + 15

After x days, the function that models how many more knots Jimmy can complete than Rick is h(x)

h(x) = f(x) - g(x) = (6x+10) - (4x+15)

       = 6x + 10 - 4x - 15

       = (6x - 4x) + (10 - 15)

       = 2x - 5


The correct answer is h(x) = 2x - 5

There are 15 rings on the laddey

10,000 hope i ! : )