What sequence of transformations, when applied to △xyz , shows that △xyz is similar to △x′y′z′ ? dilation with respect to the origin by a scale factor of 2 followed by a translation of 4 units downdilation with respect to the origin by a scale factor of 12 followed by a translation of 2 units uptranslation of 4 units down followed by a dilation with respect to the origin by a scale factor of 12translation of 4 units down followed by a dilation with respect to the origin by a scale factor of 2

The coordinates of Δxyz ⇒⇒ x(1,1)     y(2,3)    z(3,2)
The coordinates of Δx'y'z' ⇒⇒ x'(2,-2)   y'(4,2)    z'(6,0)

1. Applying the transformation of the first sentence on Δxyz
The results are ⇒⇒⇒ (2,-2)   (4,2)    (6,0)

2. Applying the transformation of the second sentence on Δxyz
The results are ⇒⇒⇒ (12,14)   (24,38)    (36,28)

3. Applying the transformation of the third sentence on Δxyz
The results are ⇒⇒⇒ (12,-36)   (24,-12)    (36,-24)

4. Applying the transformation of the fourth sentence on Δxyz
The results are ⇒⇒⇒ (2,-6)   (4,-2)    (6,-4)

By comparing the results obtained with the coordinates of Δx'y'z'
So, the correct answer is the first sentence.
dilation with respect to the origin by a scale factor of 2 followed by a translation of 4 units down

Use photo math it