Aprior study estimated as 34%. the analysts would like to conduct a second study on the same topic with a margin of error, e, of 0.027 and a confidence level of 90% (z*-score 1.645). what is the minimum sample size that should be used so the estimate of will be within the required margin of error of the population proportion? n = (1 – ) • 17 23 430 833

833

Step-by-step explanation:

When the prior population proportion (p) is known , then the formula to find the minimum sample size is given by :-

where, is the z-score for confidence level (c) and   E = the margin of error .

Given : A prior study estimated as 34%.

i.e. p= 0.34

Confidence level = 0.90

Critical z-score for 90% confidence level :

Margin of error : E= 0.027

then , the sample size =

Simplify ,

Hence, the minimum sample size=833

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)