32 points which is an equation for the line that contains the points (-3, 5) and (1, -3)? f y=-12x−32 g y=-x+2 h y=-2x−1 j y=32x−92

If we plug the x and y values of each of the given coordinate points into the right equation, we should get two valid statements:

f.  5 = -12(-3) - 32  ⇒  5 = 36 - 32  ⇒  5 ≠ 4
    -3 = -12(1) - 32  ⇒  -3 = -12 - 32  ⇒  -3 ≠ -44

g.  5 = -(-3) + 2  ⇒  5 = 3 + 2  ⇒  5 = 5
     -3 = -1 + 2  ⇒  -3 ≠ 1

h.  5 = -2(-3) - 1  ⇒  5 = 6 - 1  ⇒  5 = 5
     -3 = -2(1) - 1  ⇒  -3 = -2 - 1  ⇒  -3 = -3

The equation y = -2x - 1 contains the points (-3, 5) and (1, -3).  I didn't check the last one because I got the right answer before getting to it, but let me know if you want me to show the check.

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