You guys me this is the last question on the test

1) (1-x^2)/(1-2x)x=-2→)^2]/[1-2(-2)]=(1-4)/(1+4)=(-3)/(5)=-3/5=-0.62) (x^2-1)/(1-2x)x=-2→[(-2)^2-1]/[1-2(-2)]=(4-1)/(1+4)=(3)/(5)=3/5=0.63) (2x^2+x)/2x=-2→[2(-2)^2+(-2)]/2=[2(4)-2]/2=(8-2)/2=(6)/2=6/2=34) (3x^2+1)/[2(x-1)]x=-2→[3(-2)^2+1]/{2[(-2)-1]}=[3(4)+1]/[2(-2-1)]=(12+1)/[2(-3)]=(13)/(-6)=-13/6=-2.17answer: sequence(3x^2+1)/[2(x-1)] → (1-x^2)/(1-2x) → (x^2-1)/(1-2x) → (2x^2+x)/2

It’s 5 points actually