Write the point-slope form of the line passing through (2, -12) and parallel to y=3x. y - 12 = -(x + 2)y + 12 = -(x - 2)y + 12 = 3(x - 2)y + 12 = -3(x - 2)

The equation of the line y=3x, follows the form of y=mx+b, where m is the slope and b is the y-intercept,
Thus the slope of the equation is m=3. A line parallel to this line has a slope of 3. Thus the equation in point slope of the line parallel to y=3x that cuts through (2,-12) will be given by:
m(x-x1)=y-y1
plugging the values we obtain:
3(x-2)=y-(-12)
hence simplifying the above we get the point slope equation as:
3(x-2)=y+12

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